x^2+80x-164=0

Solution for x^2+80x-164=0 equation:

x^2+80x-164=0

a = 1; b = 80; c = -164;
Δ = b2-4ac
Δ = 802-4·1·(-164)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-84}{2*1}=\frac{-164}{2}
=-82
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+84}{2*1}=\frac{4}{2}
=2
$